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SEPARATIONS & OTHERS)

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To convert inches to millimeters:
_____inches x 25.40 = _____mm

To convert millimeters to inches:
_____mm x .0394 = _____inches


Pressure at High Altitudes

Pressure and vacuum ratings are good for sea level (14.7 psi atm. press.) only. This chart may be used to determine pressure developed at altitudes above sea level. For example, a 5 lb. machine produces 5 psi at sea level. At 5000' elevation, the same machine produces only 4.160 psi.

The following table was derived by using the head formula.

*Variations in pressure with changes in altitude are directly proportional to the relative density of the air.

The following can be used to compute atmospheric pressure at the altitudes indicated according to the relationship:

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Temperature at Higher Altitudes

Blowers are rated at standard air: .075 lbs./cubic ft.; 70F at sea level; therefore, pressures corrected to standard conditions must be used when selecting Blowers from rating tables Listed below are the factors to convert to standard conditions or curves. Caution: size motor for highest density (lowest temperature and lowest factor) condition at which it is expected to operate.

The following table was derived by using the head formula.

*Variations in pressure with changes in altitude are directly proportional to the relative density of the air.

HP1 = HP2 x factor where HP1 = horsepower at standard conditions
HP2 = horsepower at operating conditions

P1 = P2 x factor where P1 = pressure at standard conditions
P2 = pressure at operating conditions

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Value of Mercury Column

70°F in equivalent inches of water, ounces and pounds per square inch.


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Friction Loss Chart

This chart may be used to compute friction losses in a piping system. For example, determine the friction loss incurred when 70 CFM flows through a 2" pipe, 50' long.

Step 1: Intersect 70 CFM and the sloping line for 2" pipe as shown.
Step 2: Drop a vertical from this point of inter section and read the loss/100' of line, in this case, .60 Hg/100'.
Step 3: Multiply the loss/100' of line by the length of run/100'.

The loss for 50', then, is:



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